Question

Solve the following equation:

$\frac{3}{5} {y}^{2} + 15 = 0$
​

Answer 1

$\huge\bold\green{꧁}$$\sf\pink{\fbox{\sf{MsDiplomatic}}}$$\huge\bold\green{꧂}$

=> $\frac{3}{5}$y² + 15 = 0

=> $\frac{3}{5}$y² = -15

$= > {y}^{2} = \frac{ - 15}{ \frac{3}{5} }$

=> y² = -15 × $\frac{5}{3}$

=> y² = -5 × 5

=> y² = -25

=> y = √-25

• $\sf\fbox\red{ y \: = \: -5 }$ ☑️

$\huge\bold\blue{~♨~}$ $\huge\orange{ Proof }$ :-

LHS :-

• $\frac{3}{5}$y² + 15

• $\frac{3}{5}$(-5)² + 15

• $\frac{3}{5}$(-25) + 15

• 3 × (-5) + 15

• -15 + 15

• 0

Therefore, $\sf\fbox\purple{ LHS \: = \: RHS }$

$\huge\bold\green{꧁}$$\sf\pink{\fbox{\sf{MsDiplomatic}}}$$\huge\bold\green{꧂}$