Question

Solve the following equation
$\frac{3t - 2}{4} - \frac{2t + 3}{ 3} = \frac{2}{3} - t$
​

Answer 1

Step-by-step explanation:

$\frac{3t - 2}{4} - \frac{2t + 3}{ 3} = \frac{2}{3} - t$

$\mathfrak{ Taking \: \: Lcm }$

$\large\frac{3(3t - 2) - 4(2t + 3)}{12} = \frac{2 - 3t}{3}$

$\large\frac{9t - 6 - 8t - 12}{12} = 2 - 3t$

$t - 18 = 12(2 - 3t)$

$t - 18 = 24 - 36t$

$36t + t = 24 + 18$

$37t \: = 42$

$t = \frac{42}{37}$

$\mathfrak{hope \: it \: helps} \\ \mathfrak{thank \: my \: answers}$

Answer 2

Step-by-step explanation:

$\frac{3t - 2}{4} - \frac{2t + 3}{3} = \frac{2}{3} - t$

$= > \frac{3(3t - 2) - 4(2t + 3)}{12} = \frac{2 - 3t}{3}$

$= > 3(9t−6−8t−12)=12(2−3t)$

$=> - 18 - 8 = -12t - t$

$=> - 26 = - 13t$

$=> \frac{26}{13} = t</strong></p><p><strong>[tex]=> \frac{26}{13} = t$

$= > 2 = t$