Solve the following equation to prove LHS = RHS:-
(((3×-7/31)-1)/4)+(((2×-7/31)+3)/3) = ((1-(7×-7/31))/6)
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LHS = 4. RHS = (A mod C * B mod C) mod C. RHS = (4 mod 6 * 7 mod 6) mod 6. RHS = (4 * 1) mod 6. RHS = 4 ... This gives a new equation 3*2x = 3*3 mod 5 or x = 4 mod 5. 1
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Answer:tn=a+(n−1)d where n = 11, a = 5, d = - 3
Answer:tn=a+(n−1)d where n = 11, a = 5, d = - 3∴t15=5+(14)×(3)=47
Answer:tn=a+(n−1)d where n = 11, a = 5, d = - 3∴t15=5+(14)×(3)=47ANSWER IS (D) .47
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