Question

solve the following equation using cramer's rule 3x-4y =10 and 4x+3y= 5

Answer 1

Please see the attachment

Answer 2

Answer:

The solution of the system of equations is (2,-1).

Step-by-step explanation:

The given equations are

$3x-4y=10$

$4x+3y=5$

Coefficient matrix is

$D=\left[\begin{array}{cc}3&-4\\4&3\end{array}\right]$

$|D|=3\times 3-(-4)\times 4=25$

$D_x=\left[\begin{array}{cc}10&-4\\5&3\end{array}\right]$

$|D_x|=10\times 3-(-4)\times 5=50$

$D_y=\left[\begin{array}{cc}3&10\\4&5\end{array}\right]$

$|D_y|=3\times 5-10\times 4=15-40=-25$

$x=\frac{|D_x|}{|D|}=\frac{50}{25}=2$

$y=\frac{|D_y|}{|D|}=\frac{-25}{25}=-1$

Therefore the solution of the system of equations is (2,-1).