solve the following equation using elimination method y+2x-19=0 ; 2x-3y+3=0
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Bhoodhar:
and x=27/4
how
put the value of y in both of any equation
and solve it
o.ya
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Answered by
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2x+y-19=0
-2x+3y-3=0
-----------------
4y-22=0
4y=22
y=11/2
sub y=11/2 in equation 1
2x+11/2-19=0
2x=19-11/2
2x=27/2
x=27/54
x=1/2
so the values are x=1/2,y=11/2
-2x+3y-3=0
-----------------
4y-22=0
4y=22
y=11/2
sub y=11/2 in equation 1
2x+11/2-19=0
2x=19-11/2
2x=27/2
x=27/54
x=1/2
so the values are x=1/2,y=11/2
ple
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