Question

solve the following equation using quadratic equation :-48y2-13y-1=0

Answer 1

Hi ,
Given,
48y²-13y-1=0
48y²- 16y + 3y -1=0
16y(3y-1) +1(3y-1)= 0
(3y-1)(16y+1)= 0
.
hence y = -1/16 or y = 1/3.
one more method mentioned.
see picture!!.
hope it helped you!!