solve the following equation using quadratic equation :-48y2-13y-1=0
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Hi ,
Given,
48y²-13y-1=0
48y²- 16y + 3y -1=0
16y(3y-1) +1(3y-1)= 0
(3y-1)(16y+1)= 0
.
hence y = -1/16 or y = 1/3.
one more method mentioned.
see picture!!.
hope it helped you!!
Given,
48y²-13y-1=0
48y²- 16y + 3y -1=0
16y(3y-1) +1(3y-1)= 0
(3y-1)(16y+1)= 0
.
hence y = -1/16 or y = 1/3.
one more method mentioned.
see picture!!.
hope it helped you!!
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extraordinary12356:
thank u
:-)
pleasure to help!
hm.
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