Question

solve the following equation using quadratic equation:-6x2-31x+40=0

Answer 1

Heya !!!

6X² - 31X + 40 = 0

Here,

6 × 40 = 240

We try to split 240 into two parts such thar their sum or Subtraction will be 31. and their product will be 240.

Clearly,

-16 - 15 = -31

And,

-16 × -15 = 240

so,

6X² - 31X + 40

6X² - 16X - 15X + 40

2X ( 3X - 8 ) - 3 ( 3X - 8)

(3X - 8 ) ( 2X - 3) = 0

(3X -8) = 0 OR (2X -3) = 0

X = 8/3 OR X = 3/2 .


P(X) = 6X² - 31X + 40


Here,


A = Coefficient of X² = 6

B = Coefficient of X = -31


And,


C = Constant term = 40



Discriminant = B²-4AC


=> (-31)² - 4 × 6 × 40



=> 961 - 960


=> 1


Roots of the quadratic equation = -B+✓D/2A and -B-✓D/2A



=> -(-31) + ✓1 / 2 × 6 and -(-31)-✓1/2 × 6



=> 31+1/12 and 31-1/12



=> 32/12 and 30/12


=> 8/3 and 5/2.

★ HOPE IT WILL HELP YOU ★

Answer 2

it is your answer

hope are you happy