Question

Solve the following equation using transposition a/5+3=2

Answer 1

Step-by-step explanation:

find the value of a..

a/5+3=2

transposing +3 into other side , so its become -3

a/5=2-3

transposing 5 to other side,on LHS 5 is divided ..after transposing 5 become in multiplication

a=2-3×5

a=-1×5

a=-5

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Answer 2

Answer:

=> a = -5

Step-by-step explanation:

Given that:-

$\frac{a}{5} +3=2$

To find:- The value of the expression:

Here we will use the transposition method.

As we have,

=> $\frac{a}{5} +3=2$

First of all, we have to find the common denominator:

=> $\frac{a}{5} +\frac{5\times 3}{5} =2$

Simplifying it further, we get

=> $\frac{a}{5} +\frac{15}{5} =2$

Combine the fractions, we get

=> $\frac{a+15}{5} =2$

For eliminating the fraction term, we have to multiply both sides by $5$:

=> $\frac{a+15}{5} \times 5=2\times 5$

=> $a + 15= 2\times 5$

Multiply the numbers, we get

=> $a + 15 = 10$

Subtract both sides by $15$, we get

=> $a + 15 -15= 10-15$

=> $a = -5$

Hence, the required solution is -5.