Question

solve the following equation using trial and error method​

Answer 1

Answer:

Step-by-step explanation:

x/3 has to be equal to 2 in order for the LHS to be equal to 7. x then have to be 6. is this what u wanted?

Answer 2

$<i> Heya! </i>$

______________________________________________________________

→ $<u>Given Equation : </u>$

$= > \frac{x}{3} + 5 = 7$

★ Now , for solving such kinda linear equations in one variable we need to remember the following -

(+) Changes to (-)

(-) Changes to (+)

(×) Changes to (÷)

(÷) Changes to (×)

•°• By using these rules we have ,

$= > \frac{x}{3} = 7 - 5$

$= > \frac{x}{3} = 2$

★Cross Multiply the terms ,

→ x = 3 × 2

•°• $<b> <u> x = 6 </b> </u>$

★Verification ★
____________

→ Put x = 6 in the equation ,

$= > \frac{6}{3} + 5 = 7 \\ \\ = > 2 + 5 = 7$

→ 7 = 7

Hence Verified !! ✔


$<b> <u> <i> Thanks!! </b> </i> </u>$

________________________________________________________________