Solve the following equation
X^2+3x=0
Or x square plus 3 x =0
Answers
Answered by
1
x^2 + 3x = 0
x(x+3)=0
x=0,-3
x(x+3)=0
x=0,-3
Princekuldeep:
Thnx bro just forgetted how to solve
Answered by
0
x^2+3x=0
take x common
x(x+3)=0
x+3=0/x
x+3=0
x=-3
x^2+3=0
x^2=-3
x=√-3
take x common
x(x+3)=0
x+3=0/x
x+3=0
x=-3
x^2+3=0
x^2=-3
x=√-3
in last x can't be -√3 because it will be complex number that is x^2 + 3=0 => x^2 = -3=> x =√-3 which is equal 3 iota
yes its
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