solve the following equation x^2-(x+2)(x+3)/6x+1=2/3
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Answered by
11
Answer:
-20/27
Step-by-step explanation:
X² - (x+2)(x+3)/6x+1=2/3
X²-(x²+3x+2x+6)/6x+1=2/3
X² -(x²+5x+6)/6x+1=2/3
X² -x²-5x-6/6x+1=2/3
Cancel out the x²
: -5x-6=2/3 × {6x+1}
(-5x-6)= 2(6x +1)/3
3(-5x-6)=12x +2
-15x-18=12x +2
-18-2=12x +15x
-20=27x
-20/27=x
I hope you like this solution ☺
Answered by
2
Answer is -20/27 or -0•74
Hope it should be a brainliest answer.
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