Solve the following equation: x^2-(x+3)(x+3)/6x+1=2/3
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x² - (x+3)² / 6 x + 1 = 2/3
x² - (x² + 9 - 6 x) / 6 x + 1 = 2/3
(x² - x² -9 + 6 x) / 6 x + 1 = 2/3
6 x - 9 / 6 x + 1 = 2/3
18 x - 27 = 12 x + 2
6 x = 29
x = 29/6 = 4.8333
x² - (x² + 9 - 6 x) / 6 x + 1 = 2/3
(x² - x² -9 + 6 x) / 6 x + 1 = 2/3
6 x - 9 / 6 x + 1 = 2/3
18 x - 27 = 12 x + 2
6 x = 29
x = 29/6 = 4.8333
Anonymous:
thanks
Answered by
1
x^2-x^2+3x +2x + 6/ 6x+1= 2/3
5x + 6/6x +1= 2/3
15x+18=12x+2
15x-12x=18-2
3x= 16
x=0.1875
5x + 6/6x +1= 2/3
15x+18=12x+2
15x-12x=18-2
3x= 16
x=0.1875
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