solve the following equation
(x-3)(x+1)(x-2)(x-9)>=0
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EXPLANATION.
Equation.
⇒ (x - 3)(x + 1)(x - 2)(x - 9) > 0.
As we know that,
First we find the zeroes of the equation, we get.
⇒ x - 3 = 0.
⇒ x = 3. - - - - - (1).
⇒ x + 1 = 0.
⇒ x = -1. - - - - - (2).
⇒ x - 2 = 0.
⇒ x = 2. - - - - - (3).
⇒ x - 9 = 0.
⇒ x = 9. - - - - - (4).
All the zeroes of the equation we can put it on wavy curve method, we get.
x ∈ (-∞,-1) ∪ (2,3) ∪ (9,∞).
MORE INFORMATION.
Inverse of a relation.
Let A, B be two sets and let R be a relation from set A to B. Then the inverse of R, denoted by R⁻¹, is a relation from B to A and is defined by R⁻¹ = {(b, a) : (a, b) ∈ R}, Clearly,
(a, b) ∈ R ⇔ (b, a) ∈ R⁻¹ Also,
Domain of R = Range of R⁻¹ and,
Range of R = Domain of R⁻¹.
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