Question

Solve the following equation x+4y = 27xy and x+2y = 21xy​

Answer 1

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$\red{\bold{\underline{\underline{❥Question᎓}}}}$Solve the following equation x+4y = 27xy and x+2y = 21xy

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x+4y=27xy......(I)

x+2y=21xy...........(ii)

Now substract equation( ii) from (ii)

x+4y=27xy

(-)x+2y=21xy

we get 2y=6xy

cancel y from both sides

we get :-2=6x

x=1/3............(iii)

Now finding Y's value

put x values in equation (I)

$⟹ \frac{1}{3} + 4y = 27 \times \frac{1}{3} \times y$

$⟹\frac{1 + 12y}{3} = 9y$

$⟹1 + 12y = 27y$

$⟹15y = 1$

$⟹y = \frac{1}{15}$

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