Math, asked by vdeepya, 9 months ago

Solve the following equation:
x+a/x-a=b-a/b+a

Answers

Answered by MaryTaniya
2

Answer:

x+a/x-a=b-a/b+a

(x+a)(b+a) = (b-a)(x-a)

xb+xa+ab+a^2 = bx-ab-ax+a^2

xb-bx+xa+ax+ab+ab+a^2-a^2 = 0

2xa+2ab = 0

2a(x+b) = 0

2a = 0 ,x+b = 0

a = 0 x = -b

Answered by Suma06
0

ANSWER :

 \frac{x + a}{x - a}  =  \frac{b - a}{b + a}  \\  (x + a)(b + a) = (b - a)(x - a) \\ bx + ax + ab +  {a}^{2}   = bx - ab - ax +  {a}^{2}  \\ bx - bx + ax + ax + ab + ab +  {a}^{2}  -  {a}^{2}  = 0 \\ 2ax + 2ab = 0 \\ 2a(x + b) = 0

This can't be simplified more.....

I think this the simplification.

Please mark this answer as the brainliest.

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