Question

solve the following equation.

x²+3x+1=(x-2)²​

Answer 1

Answer:

x2+3x+1=(x−2)2

x2+3x+1=x2−4x+4

⇒x2+3x+1−x2+4x−4=0

⇒7x−3=0 has its highest power 1

Hence it is not a quadratic equation.

Answer 2

${x}^{2} + 3x + 1 = ({x - 2})^{2}$

Using identity a²-2ab+b² to break (x-2)²

$\cancel{ {x}^{2}} + 3x + 1 = \cancel{ {x}^{2} } - 2x + 4$

$3x + 2x = 4 - 1$

$5x = 3$

$x = \frac{3}{5}$

$x = 0.6$