Math, asked by muhammadasharhussain, 2 months ago

Solve the following equation:Y2 + 8y + 16 = 0
(-4 , -4)
(4 , 4)
(4 , -4)
(-4 , 4)

Answers

Answered by kaushalrathod311
1

Answer:

y2 - 8y + 16 = 0

y2 - 4y - 4y + 16 = 0

y(y-4) -4 (y-4) = 0

(y-4) (y-4) = 0

y = 4 or y = 4.

Answered by AayushJp
0

Answer:

(-4 , -4 )

Step-by-step explanation:

y2 + 8y + 16 = 0

y2 + 4y + 4y + 16 = 0

Taking y common

y ( y + 4 ) + 4 ( y + 4 ) = 0

( y + 4 ) (y + 4 ) = 0

Hence y = -4 , -4

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