Math, asked by sibaprasad3513, 3 months ago

Solve the following equation:
z/5-3/5=-2z/3+1/6
2/3-3y/2+1/3 y+4=0
3(x-2/3)=3/4 x+21/4
3(x-4)+2(2x+1)=11
2x^2+3x-10=x^2+6x+30

Answers

Answered by anjaligupta23feb2004

0

There you go!!

Hope your day goes well!!

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