Question

Solve the following equations:
(1)17 (x +4) + 8 ( x +6) = 11( x +5) +15 (x +3)
(2) 3y/2 + (y + 4)/4 = 5 - (y-2)/4
(3) 5(1-2 x) = 9(1-x)

Answer 1

Answer:

(1) x = 16

(2) $y\ =\ \dfrac{9}{4}$

(3)  x = -4

Step-by-step explanation:

(1) 17 (x +4) + 8 ( x +6) = 11( x +5) +15 (x +3)

  => 17x + 68 + 8x + 48 = 11x + 55 + 15x + 45

  => 25x + 116 = 26x + 100

  => 116- 100 = 26x - 25x

  => 16 = x

Hence, the value of x will be 16.

(2) 3y/2 + (y + 4)/4 = 5 - (y-2)/4

$=> \dfrac{2\times 3y\ +(y+4)}{4}\ =\ \dfrac{20-(y-2)}{4}$

=> 6y + y+4 = 20 - y+ 2

=> 7y + 4 = -y + 22

=> 8y = 18

$=>\ y\ =\ \dfrac{18}{8}\ =\ \dfrac{9}{4}$

Hence, the value of y will be $\dfrac{9}{4}.$

(3) 5(1-2 x) = 9(1-x)

   => 5 - 10x = 9 - 9x

   => 5 - 9 = 10x - 9x

    => x = -4

Hence, the value of x will be -4.