Question

solve the following equations 1 ) 2 X + 10 =30 . 2) p-3=7 . 3)3m-3=9 .4) 2L+3=7 .5)2t/5=4 . hey please give the answer of all pls
​

Answer 1

Answer:

1)2x+10=30

2x=30-10

2x=20

x=10

2)p-3=7

p=7+3

p=10

3)3m-3=9

3m=9+3

3m=12

m=4

4)2l+3=7

2l=7+3

2l=10

l=5

5)2t/5=4

2t=20

t=10

Answer 2

$\large\sf\underline{How\:to\:do\:?}$

In this question we are given equation with one variable. We need to find the value of the variables. In order to do so we will transpose the terms, do some calculations and get out answers. Let's begin !

‎

$\small\sf\underline{Question\:1\::}$

• $\bf\:2x+10=30$

$\small\sf\underline{Solution\::}$

$\sf\:2x+10=30$

• Transposing + 10 to the other side it becomes -10

$\sf\longrightarrow\:2x=30-10$

$\sf\longrightarrow\:2x=20$

• Transposing 2 to other side it goes to the denominator

$\sf\longrightarrow\:x=\frac{20}{2}$

• Reducing it to lower terms

$\sf\longrightarrow\:x=\cancel{\frac{20}{2}}$

$\small{\underline{\boxed{\mathrm\red{\longrightarrow\:x=10}}}}$ ✧

___________________________‎

‎

$\small\sf\underline{Question\:2\::}$

• $\bf\:p-3=7$

$\small\sf\underline{Solution\::}$

$\sf\:p-3=7$

• Transposing - 3 to the other side it becomes + 3

$\sf\longrightarrow\:p=7+3$

$\small{\underline{\boxed{\mathrm\red{\longrightarrow\:p\:=\:10}}}}$ ✧

___________________________‎

‎

$\small\sf\underline{Question\:3\::}$

• $\bf\:3m-3=9$

$\small\sf\underline{Solution\::}$

$\sf\:3m-3=9$

• Transposing - 3 to the other side it becomes +3

$\sf\longrightarrow\:3m=9+3$

$\sf\longrightarrow\:3m=12$

• Transposing 3 to other side it goes to the denominator

$\sf\longrightarrow\:m=\frac{12}{3}$

• Reducing it to lower terms

$\sf\longrightarrow\:m=\cancel{\frac{12}{3}}$

$\small{\underline{\boxed{\mathrm\red{\longrightarrow\:m=4}}}}$ ✧

___________________________‎

‎

$\small\sf\underline{Question\:4\::}$

• $\bf\:2l+3=7$

$\small\sf\underline{Solution\::}$

$\sf\:2l+3=7$

• Transposing + 3 to the other side it becomes - 3

$\sf\longrightarrow\:2l=7-3$

$\sf\longrightarrow\:2l=4$

• Transposing 2 to other side it goes to the denominator

$\sf\longrightarrow\:l=\frac{4}{2}$

• Reducing it to lower terms

$\sf\longrightarrow\:l=\cancel{\frac{4}{2}}$

$\small{\underline{\boxed{\mathrm\red{\longrightarrow\:l=2}}}}$ ✧

___________________________‎

‎

$\small\sf\underline{Question\:5\::}$

• $\bf\:\frac{2t}{5}=4$

$\small\sf\underline{Solution\::}$

$\sf\longrightarrow\:\frac{2t}{5}=4$

• Cross multiplying

$\sf\longrightarrow\:2t=4 \times 5$

$\sf\longrightarrow\:2t=20$

• Transposing 2 to other side it goes to the denominator

$\sf\longrightarrow\:t=\frac{20}{2}$

• Reducing it to lower terms

$\sf\longrightarrow\:t=\cancel{\frac{20}{2}}$

$\small{\underline{\boxed{\mathrm\red{\longrightarrow\:t=10}}}}$ ✧

___________________________‎

Not sure about the ansWers !?

Let's verify it :

Equation 1 : $\bf\:2x+10=30$

We got x as 10 .

So let's plug the value of x as 10 in the equation.

$\sf\leadsto\:2(10)+10=30$

$\sf\leadsto\:2 \times 10+10=30$

$\sf\leadsto\:20+10=30$

$\sf\leadsto\:30=30$

$\bf\leadsto\:LHS=RHS$

$\dag\:\underline{\sf hence\:verified}$

===============

Equation 2 : $\bf\:p-3=7$

We got p as 10 .

So let's plug the value of p as 10 in the equation.

$\sf\leadsto\:10-3=7$

$\sf\leadsto\:7=7$

$\bf\leadsto\:LHS=RHS$

$\dag\:\underline{\sf hence\:verified}$

===============

Equation 3 : $\bf\:3m-3=9$

We got m as 4 .

So let's plug the value of m as 4 in the equation.

$\sf\leadsto\:3(4)-3=9$

$\sf\leadsto\:3 \times 4-3=9$

$\sf\leadsto\:12-3=9$

$\sf\leadsto\:9=9$

$\bf\leadsto\:LHS=RHS$

$\dag\:\underline{\sf hence\:verified}$

===============

Equation 4 : $\bf\:2l+3=7$

We got l as 2 .

So let's plug the value of l as 2 in the equation.

$\sf\leadsto\:2(2)+3=7$

$\sf\leadsto\:2 \times 2+3=7$

$\sf\leadsto\:4+3=7$

$\sf\leadsto\:7=7$

$\bf\leadsto\:LHS=RHS$

$\dag\:\underline{\sf hence\:verified}$

===============

Equation 5 : $\bf\:\frac{2t}{5}=4$

We got t as 10 .

So let's plug the value of t as 10 in the equation.

$\sf\leadsto\:\frac{2(10)}{5} = 4$

$\sf\leadsto\:\frac{2 \times 10}{5} = 4$

$\sf\leadsto\:\cancel{\frac{20}{5}} = 4$

$\sf\leadsto\:4=4$

$\bf\leadsto\:LHS=RHS$

$\dag\:\underline{\sf hence\:verified}$

===============

‎

!! Hope it helps !!