Math, asked by anuhya05ks, 1 year ago

solve the following equations

1. 3[n-5]=21



Raja395: If it is 3[n-5] = 21
Raja395: Then, n-5 = 7
Raja395: n = 12

Answers

Answered by ArijitPatra
10
3(n-5) = 21
n-5 =21/3
n-5 = 7
n= 5+7
n= 12
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