Solve the following equations 1 a) 1/4 y +9 = 6
b)3( 2x -1) =1
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Step-by-step explanation:
Given:-
a) 1/4 y +9 = 6
b)3( 2x -1) =1
To find:-
Solve the following equations
Solution:-
a)
Given equation is 1/4 y +9 = 6
=> 1/4 y = 6-9
=> 1/4 y = -3
=> y = -3×4
=> y = -12
The value of y = -12
Check:-
LHS:-
1/4 y+9
Put y = -12 then
=> 1/4 (-12)+9
=> (-12/4)+9
=>>(-3)+9
=> 6
=> RHS
LHS = RHS is true for y = -12
b)
Given equation is 3(2x-1 ) = 1
=> 6x -3 = 1
=> 6x = 1+3
=> 6x = 4
=> x = 4/6
=> x = 2/3
The value of x = 2/3
Check:-
LHS:-
3(2x-1)
Put x = 2/3 then
=> 3[2(2/3)-1]
=>3[(4/3)-1]
=> 3[(4-3)/3]
=> 3[1/3]
=> 3/3
=> 1
=> RHS
LHS= RHS is true for x = 2/3
Answer:-
a) The solution of 1/4 y +9 = 6 is -12
b) The solution of 3( 2x -1) =1 is 2/3
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