Math, asked by saiktdas901532, 20 days ago

Solve the following equations (1 tb 11):

5x - 3=3x - 5

4(2x + 1)=3(x-1) + 7

5y - 2[y - 3(y - 5)=6

3x - 7=3(5 - x)

3(2p - 1) = 5-(3p - 2).

0.3(6-x) =0.4 (x+8)​

Answers

Answered by pallavisaini15
0

Answer:

1. 5x-3=3x-5

5x-3x=-5+3

2x=-2

x=-1

2. 4(2x+1)=3(x-1)+7

8x+4=3x-3+7

8x-3x=0

4x=0

x=0

3. 5y-2[y-3(y-5)]=6

5y-2(y-3y+15)=6

5y-2y+6y-30=6

9y=36

y=4

4. 3x-7=15-3x

6x=22

x=11/3

5. 6p-3=5-3p+2

9p=10

p=10/9

6. 1.8-0.3x=0.4x+3.2

-1.4=0.7x

x=-2

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