Question

Solve the following equations : -

1. $\frac{1}{2} (p - 1) = 2$

2. $\frac{1}{5}( - 1 - 2n) = - 3$

pls answer it.....​
it is urgent....

Answer 1

Answer- The above question is from the chapter 'Linear Equations in One Variable'.

Given question: Solve the following equations :-

1. $\frac{1}{2}$ (p - 1) = 2

2. $\frac{1}{5}$ (- 1 - 2n) = -3

Solution: 1.  $\frac{1}{2}$ (p - 1) = 2

⇒ p - 1 = 2 × 2

p - 1 = 4

Transposing 1 to R.H.S, we get,

p = 1 + 4

p = 5

∴ Value of p = 5.

2. $\frac{1}{5}$ (- 1 - 2n) = - 3

⇒ - 1 - 2n = - 3 × 5

- 1 - 2n = - 15

Taking out - common, we get,

(1 + 2n) = 15

Transposing 1 to R.H.S., we get,

2n = 15 - 1

2n = 14

n = 14 ÷ 2

n = 7

∴ Value of n = 7.