Question

solve the following equations

2. 16-2(3y+5)=4(y-2)

plzzzz tell me the answer
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Answer 1

Step-by-step explanation:

${:}\longrightarrow\sf 16-2 (3y+5)=4(y-2)$

${:}\longrightarrow\sf 14 (3y+5)=4y-8$

${:}\longrightarrow\sf 42y+70=4y-8$

${:}\longrightarrow\sf 42y-4y=-8-70$

${:}\longrightarrow\sf 38y=-78$

${:}\longrightarrow\sf y=\dfrac {-78}{38}$

${:}\longrightarrow\sf y=\dfrac{-39}{19}$