Question

Solve the following equations. ​

Answer 1

• $x(x + 1) = {x}^{2} + x$
• $x(x + 2) = {x}^{2} + 2x$

$x(x + 1) - x(x + 2) + 3x = 6$

$\implies$ ${x}^{2} + x - {x}^{2} - 2x + 3x = 6$

$\implies$ $2x = 6$

$\implies$ $x = \frac{6}{2}$

Hence, $x = 3$

$<marquee>#Shruti$

Answer 2

Step-by-step explanation:

=>x(x+1)-x(x-2)+3x=6

=> x2+x-x2+2x+3x=6

=> x2-x2-x+2x+3x=6

=>-x+5x=6

=>2x=6

=>x=6/2

=>x=3

hope it help u .................

• √\_____anushka❤