Math, asked by tamilaarasis, 2 months ago

Solve the following equations:2x^3+3x^2+3x+1=0

Answers

Answered by Anonymous
0

Answer:

x= 5,-2

Step-by-step explanation:

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Answered by Everyknowledge
0

Answer... please give me brainlist

Step-by-step explanation:

ol:

(2x + 3) (3x + 1) = 0

2x(3x + 1) + 3(3x + 1) =0

6x² + 2x + 9x + 3 = 0

6x² + 11x + 3 = 0

6x² + 9x + 2x + 3 =0

3x(2x + 3) + 1(2x + 3)

( 2x+ 3) , (3x + 1) = 0

2x + 3 =0 or 3x +1 = 0

2x = -3 or 3x = -1

x = -3/2 or x = -1/2

Ans. x = -3/2 or x = -1/2

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