Question

Solve the following equations:
3x + 2y = 0
2x + 3y = 0​

Answer 1

3x+2y = 0 -----eq.1

2x+3y = 0 -----eq.2

form eq.1

x = -2y/3 -----eq.3

now.. substitute the value of x in eq.2

=> 2(-2y/3+3y) = 0

=> -4y/3+3y = 0

=> -4y+9y = 0

=> 5y = 0

=> y = 0

now substitute the value of y in eq.3

=> x = -2×0/3

=> x = 0

so value of x = 0 and y = 0

Answer 2

Answer:

$\huge{\boxed{\rm{\red{solution=(0,0)}}}}$

Step-by-step explanation:

Given equations are

3x+2y=0-----(1)

2x+3y=0----(2)

adding (1)&(2)

=>5x+5y=0

=>5(x+y)=0

=>x+y=0.....(3)

subtracting (2) from (1)

=>3x-2x+2y-3y=0

=>x-y=0-----(4)

From(3)&(4)

x+y=0

x-y=0

----------

2x+0=0

=>2x=0

=>x=0/2

Therefore ,x=0

and from(3)

0+y=0

=>y=0

The solution is (0,0)