solve the following equations:3x-y=2,x+2y=10
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3x - y = 2 ...eq1
x + 2y = 10 ...eq2
Multiplying eq2 by 3
3x - y = 2
3x + 6y = 30
Now Subtracting both of equations
-y - 6y = 2-30
-7y = -28
y = 28/7
y= 4
Putting value of y in eq2
x + 2 x 4 = 10
x+8 = 10
x = 2
@Abhinav
x + 2y = 10 ...eq2
Multiplying eq2 by 3
3x - y = 2
3x + 6y = 30
Now Subtracting both of equations
-y - 6y = 2-30
-7y = -28
y = 28/7
y= 4
Putting value of y in eq2
x + 2 x 4 = 10
x+8 = 10
x = 2
@Abhinav
842abhinavkumar:
I hope every step is clear
if there is any confusion you can ask
ok.....
: )
: )
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