Question

solve the following equations: 4-3(x-2)=2​

Answer 1

Answer:

4-3x+6=2

10-3x=2

-3x=-8

x=8/3

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Answer 2

Here it is given that,

We have to solve the given equation

As we have,

$4-3(x-2)=2$

For solving the above equation we have to use the rule of BODMAS,

Now, by distributing the terms,

$=>4-(3x+3\times-2)=2$

$=>4-(3x-6)=2$

Expanding the parenthesis,

$=>4-3x+6=2$

Grouping the like terms,

$=>-3x+(4+6)=2$

By simplifying it further,

$=>-3x+10=2$

Now, subtract both sides by $10$ we get,

$=>-3x+10-10=2-10$

$=>-3x=-8$

Divide both the sides by $-3$ we get,

$=>\frac{-3x}{-3}=\frac{-8}{-3}$

Cancel the negative signs,

$=>\frac{3x}{3}=\frac{8}{3}$

So, we get

$=>x=\frac{8}{3}$

Hence, the required solution is $\frac{8}{3}.$