Question

solve the following equations​

Answer 1

Answer:

The answer of the given equation is $\frac{-2}{3}$

Step-by-step explanation:

Given:

$\frac{2y-3}{4} - \frac{y-2}{2} = \frac{6y+5}{4}$

On LHS, the LCM of 4 and 2 is 4.

⇒ $\frac{(2y-3)-2(y-2)}{4} = \frac{6y+5}{4}$

⇒ $\frac{(2y-3)-(2y-4)}{4} = \frac{6y+5}{4}$$\frac{1}{4} = \frac{6y+5}{4}$

⇒ $\frac{(2y-3-2y+4)}{4} = \frac{6y+5}{4}$

⇒ $\frac{1}{4} = \frac{6y+5}{4}$

∵ The denominator is same on LHS and RHS,

⇒ 1 = 6y + 5

⇒ 6y = 1 - 5

⇒ 6y = - 4

⇒ y = $\frac{-4}{6}$

⇒ y = $\frac{-2}{3}$

∴ The answer of the given equation is $\frac{-2}{3}$