Math, asked by sriramathulp266b0, 1 year ago

Solve the following equations 5/x-1+1/y-2=2 6/x-1-3/y-2=1

Answers

Answered by Anant02
71
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sriramathulp266b0: Thanks
Answered by pinquancaro
42

Answer:

The solution of the equation is x=4 and y=5.  

Step-by-step explanation:

Given : Equations \frac{5}{x-1}+\frac{1}{y-2}=2 and \frac{6}{x-1}-\frac{3}{y-2}=1

To find : Solve the following equation ?

Solution :

For simpler calculation,

Put X=\frac{1}{x-1} and Y=\frac{1}{y-2}

Now, Substitute in the given equations,

\frac{5}{x-1}+\frac{1}{y-2}=2....(1)

5X+Y=2 .....(3)

\frac{6}{x-1}-\frac{3}{y-2}=1 .....(2)

6X-3Y=1......(4)

Solving (3) and (4),

Multiply equation (3) by 3 and add (4) from it,

15X+3Y+6X-3Y=6+1

21X=7

X=\frac{7}{21}=\frac{1}{3}

Substitute in (3),

5(\frac{1}{3})+Y=2

\frac{5}{3}+Y=2

Y=2-\frac{5}{3}

Y=\frac{1}{3}

Substitute in the condition,

X=\frac{1}{x-1}

\frac{1}{3}=\frac{1}{x-1}

x-1=3

x=4

and  Y=\frac{1}{y-2}

\frac{1}{3}=\frac{1}{y-2}

y-2=3

y=5

Therefore, The solution of the equation is x=4 and y=5.

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