Solve the following equations:
5x + 3y = -11; 2x + 4y = -10
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5x + 3y = -11 _______( i)
2x + 4 y = -10 _______ ( ii )
from equation ( i )
x = -11 - 3y / 5 _______( iii )
substituting the value of x in equation ( ii )
2x + 4y = -11
2 × (-11 -3 y / 5 ) + 4y = -10
- 22 - 6y / 5 + 4y = -10
-22 - 6y + 20 y /5 = -10
-22 -6y + 20y = -10 × 5
-22 + 14y = -50
14y = -50 + 22
14y = - 28
y = -28 / 14
y = - 2 _______ ( iv )
substituting the value of y in equation ( iii )
x = -11 - 3y / 5
x = -11 - 3 × -2 / 5
x = -11 + 6 / 5
x = -5 /5
x= -1
hence , x = -1 and y = -2
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