Question

solve the following equations
(5y–7)-(2y-35)=3-(1-4y)​

Answer 1

Step-by-step explanation:

(5y-7)-2y+35=-3+4y

5y-7=-3+4y+2y+35

5y-7= 6y+32

-7-32=6y-5y

-39=y

y = -39

Answer 2

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

$\sf \longmapsto(5y - 7) - (2y - 35) = 3 - (1 - 4y)$

=>expanding the terms and removing brackets:-

$\sf \longmapsto5y - 7 - 2y + 35 = 3 - 1 + 4y$

$\sf \longmapsto5y - 7 - 2y + 35 - 3 + 1 - 4y = 0$

Now , arrange like terms together:

$\sf \longmapsto5y - 2y - 4y - 7 + 35 - 2 = 0$

$\sf \longmapsto3y - 4y + 28 - 2 = 0$

$\sf \longmapsto - y + 26 = 0$

$\sf \longmapsto - y = - 26$

$\sf \bold{ \red{y = 26}}$

Check

$\sf \longmapsto(5y - 7) - (2y - 35) = 3 - (1 - 4y)$

$\sf \longmapsto(5 \times { \red{26}} - 7) - (2 \times { \red{26}} - 35) = 3 - (1 - 4 \times { \red{26}})$

$\sf \longmapsto(130 - 7) - (52 - 35) = 3 - (1 - 104)$

$\sf \longmapsto123 - 17 = 3 - ( - 103)$

$\sf \longmapsto106 = 3 + 103 = 106$