Question

solve the following equations 9t-7/3t+5=3t-4/t+6
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Answer 1

9t-7/3t+5=3t-4/t-6

We move all terms to the left:

9t-7/3t+5-(3t-4/t-6)=0

Domain of the equation: 3t!=0

t!=0/3

t!=0

t∈R

Domain of the equation: t-6)!=0

t∈R

We get rid of parentheses

9t-7/3t-3t+4/t+6+5=0

We calculate fractions

9t-3t+(-7t)/3t^2+12t/3t^2+6+5=0

We add all the numbers together, and all the variables

6t+(-7t)/3t^2+12t/3t^2+11=0

We multiply all the terms by the denominator

6t*3t^2+(-7t)+12t+11*3t^2=0

We add all the numbers together, and all the variables

12t+6t*3t^2+(-7t)+11*3t^2=0

Wy multiply elements

18t^3+33t^2+12t+(-7t)=0

We get rid of parentheses

18t^3+33t^2+12t-7t=0

We do not support etpression: t^3