Question

solve the following equations- a) 10=4+3(t+2) b) 28=4+3 (t+5) WHOEVER WILL ANSWER THIS QUESTION WILL BE THE BRAINLIEST PLEASE ANSWER CORRECTLY.​

Answer 1

Answer:

Step-by-step explanation:

a)   10 = 4 + 3(t+2)

     10 = 4 + 3t + 6   add 4+6

    10 = 10 + 3t   subtract 10 on both sides

    0 = 3t   divide 3 on both sides

    0 = t

b)   28 = 4 + 3(t+5)

     28 = 4 + 3t + 15   add 4+15

     28 = 19 + 3t   subtract 19 on both sides

     9 = 3t   divide 3 on both sides

    3 = t

Answer 2

The correct answer is 0 and 3 respectively.

Given: a) 10 = 4 + 3(t + 2)

b) 28=4+3 (t+5)

To Find: Value of t in both the equations.

Solution:

a) 10 = 4 + 3(t + 2)

6 = 3(t + 2)

2 = t + 2

t = 0

b) 28=4+3 (t+5)

24 = 3(t + 5)

8 = t + 5

t = 3

Hence, the value of both the equations is 0 and 3 respectively.

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