Question

Solve the following equations : (a) 10 = 4+3 (t + 2) (b) 7x = 13x - 12 (c) If k +7 = 10, then find the value of 9k - 50​

Answer 1

(a) 10 = 4 + 3 (t + 2)

10 = 7 (t + 2)

10 = 7t + 14

10 - 14 = 7t

- 4 = 7t

t = - 4 / 7

(b) 7x = 13x - 12

7x - 13x = - 12

- 6x = - 12

x = - 12 / - 6

x = 12 / 6

x = 2

(c) k + 7 = 10

k = 10 - 7

k = 3

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Answer 2

Answer:

ஃ a) t = 0

b) x = -2

c) k = 3 and the answer of the given equation is -23.

Step-by-step explanation:

a) 10 = 4 + 3 ( t + 2 )

10 = 4 + 3t + 6

10 = 10 + 3t

3t = 10 - 10

3t = 0

$\sf t = \frac{0}{3} = 0$

b) 7x = 13x - 12

13x - 7x = -12

6x = -12

$\sf x = \frac{ - 12}{6} = - 2$

c) k + 7 = 10

k = 10 - 7 = 3

The value of k is 3, now we can find 9k - 50

9k - 50

9 ( 3 ) - 50

27 - 50 = -23