Question

Solve the following equations
a) 10 = 4 + 3( t + 2)
b) n + 1 = 19​

Answer 1

♥HEY♥

☞Answer

$a) \: 10 = 4 + 3(t + 2) \\ 10 = 4 + 3t + 6 \\ 10 = 10 + 3t \\ 10 - 10 = 3t \\ = 3t \\ \\ \\ b) \: n + 1 = 19 \\ n = 19 - 1 \\ n = 18$

THANKS❤

Answer 2

Answer:

♥HEY♥

☞Answer

\begin{gathered}a) \: 10 = 4 + 3(t + 2) \\ 10 = 4 + 3t + 6 \\ 10 = 10 + 3t \\ 10 - 10 = 3t \\ = 3t \\ \\ \\ b) \: n + 1 = 19 \\ n = 19 - 1 \\ n = 18\end{gathered}

a)10=4+3(t+2)

10=4+3t+6

10=10+3t

10−10=3t

=3t

b)n+1=19

n=19−1

n=18

THANKS❤

Step-by-step explanation:

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