Math, asked by dhruvrajpurohit04, 8 months ago

Solve the following equations:

(a) 2(x + 26) = 46

(b) 3(n – 64) = 30​

Answers

Answered by Anonymous
13

Answer:

Given,

1. 2(x+26) = 46

=> 2x + 52 = 46

=> 2x = 46 - 52

=> x = -6/2

=> x = -3.

2. 3(n-64) = 30

=> 3n - 192 = 30

=> 3n = 192+30

=> n = 222/3

=> n = 74.

Step-by-step explanation:

Hope it helps you....

Answered by balwinderkaurbhatti
5

Answer:

(a) 2x+52 = 46

2x = 46-52

2x = -6

x = -6/2

x= -3

(b) 3(n-64) = 30

3n-192 = 30

3n = 192+30

3n = 222

n = 222/3

n = 74

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