Question

Solve the following equations: a. 3x – 2 (x + 3) = 2 (2x - 5) - 8​

Answer 1

3x – 2 × 2x + 2 × 5 = 2 × x + 2 × 3 – 8 3x – 4x + 10 = 2x + 6 – 8 -x + 10 = 2x – 2 Transposing x to RHS and 2 to LHS, we get 10 + 2 = 2x + x 3x = 12 Dividing both sides by 3, we get 3x/3 = 12/3 x = 4 Verification: Substituting x = 4 on both sides, we get 3(4) – 2{2(4) – 5} = 2(4 + 3) – 8 12 – 2(8 – 5) = 14 – 8 12 – 6 = 6 6 = 6 Thus LHS = RHS Hence, verified.Read more on Sarthaks.com - https://www.sarthaks.com/684605/solve-the-equation-also-verify-the-result-3x-2-2x-5-2-x-3-8