Math, asked by technicalbrowser627, 5 hours ago

Solve the following equations and check the result (method of transposition a) 9(a+3)+7=22 b) 25-18-7(b-6)​​

Answers

Answered by rkkirthana
3

Answer:

a) -4/3

b) 7

Step-by-step explanation:

a) 9(a+3) + 7 = 22

Multiply 9 inside the braces,

9a + 27 + 7 = 22

Keeping the variable in LHS,

9a = 22 - 7 -27

9a = -12

a = -12/9

a = -4/3 or -1.33

b) 25-18 = 7(b-6)

7 = 7b - 42

7 + 42 = 7b

49 = 7b

b = 7​​

Answered by amitnrw
4

Given :  

a) 9(a+3) + 7 = 22

b) 25 = 18 - 7(b-6)​   ( correction)

https://brainly.in/question/47882286  

To Find :   Solve the following equations  using method of transposition

Verify the result

Solution:

a) 9(a+3) + 7 = 22

Using distributive property

9a + 27 + 7 = 22

=> 9a + 34 = 22

Transpose 34 on RHS

=> 9a = 22 - 34

=> 9a = - 12

Transpose 9

=> a = - 12/9

=> a = -4/3

9(a+3) + 7 = 22

Substitute a = -4/3 in LHS

LHS = 9( -4/3 + 3) + 7

= -12 + 27 + 7

= 15 + 7

= 22

= RHS

Verified

b)

25 = 18 - 7(b-6)​

Transpose 18 on LHS

=> 25 - 18 = -7(b  - 6)

=> 7 = -7(b - 6)

transpose - 7

=> 7/(-7) = b - 6

=> - 1 = b - 6

Transpose -6

=> -1 + 6 = b

=> 5 = b

=> b = 5

25 = 18 - 7(b-6)​

Substitute b = 5 in RHS

RHS = 18 - 7(5 - 6)

= 18 - 7(-1)

= 18 + 7

= 25

= LHS

Verified

a = -4/3  and b = 5

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