solve the following equations and check the solutions: a) 5 - 3(5x+2) =4(7 -3x) +1 b) 6x+1÷3+1=x-3÷6
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Answer:
Let T1 = a, common difference = d
Tm => a+(m-1)d = 1/n…(i)
Tn => a+(n-1)d = 1/m…(ii)
(i) – (ii)
[(m-1)-(n-1)]d = (1/n)-(1/m)
(m-n)d = (m-n)/mn
d = 1/mn
Substitute d in (i)
a+(m-1)(1/mn) = 1/n
a+(m/mn)-1/mn = 1/n
a+(1/n)-1/mn = 1/n
a = 1/mn
a-d = (1/mn)-(1/mn) = 0
Hence option (2) is the answer.
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