Question

solve the following equations and verify the solutions. 2/3x+5=1/5-2x.
please verify this and also in solution
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Answer 1

hope this answer will help you

Answer 2

★ Solution :-

In the question, we're given with an equation which has two same variables x. We should find the values of those. We have two methods to solve this question.

The first method is as follows,

$\sf \leadsto \dfrac{2}{3}x + 5 = \dfrac{1}{5} - 2x$

$\sf \leadsto \dfrac{2x}{3} + 5 = \dfrac{1}{5} - 2x$

$\sf \leadsto \dfrac{2x + 15}{3} = \dfrac{1 - 10x}{5}$

$\sf \leadsto 5(2x + 15) = 3(1 - 10x)$

$\sf \leadsto 10x + 75 = 3 - 30x$

$\sf \leadsto 10x + 30x = 3 - 75$

$\sf \leadsto 40x = -72$

$\sf \leadsto x = \dfrac{-72}{40}$

$\sf \leadsto x = \dfrac{-9}{5}$

The second method is as follows,

$\sf \leadsto \dfrac{2}{3}x + 5 = \dfrac{1}{5} - 2x$

$\sf \leadsto \dfrac{2x}{3} + 2x = \dfrac{1}{5} - 5$

$\sf \leadsto \dfrac{2x + 6x}{3} = \dfrac{1 - 25}{5}$

$\sf \leadsto \dfrac{8x}{3} = \dfrac{-24}{5}$

$\sf \leadsto 5(8x) = 3(-24)$

$\sf \leadsto 40x = -72$

$\sf \leadsto x = \dfrac{-72}{40}$

$\sf \leadsto x = \dfrac{-9}{5}$

Therefore, the value of x is $\sf \dfrac{-9}{5}$