Question

Solve the following equations and verify your answer: 1. (2x-3)/(3x+2) = -2/3 2. (2-y)/(y+7)=3/5 3. (5x-7)/(3x) = 2 4. (3x+5)/(2x + 7) = 4 5. (2y + 5)/(y + 4) = 1​

Answer 1

Answer:

$Solve \: the \: following \: equations \: and \: verify \: your \: answer: \\ 1). \frac{(2x - 3)}{(3x + 2)} = \frac{ - 2}{3} \\ 3(2x - 3) = - 2(3x + 2) \\ 6x - 9 = - 6x - 4 \\ 6x + 6x = 9 - 4 \\ 12x = 5 \\ x = \frac{5}{12}$

$2). \frac{(2 - y)}{(y + 7)} = \frac{3}{5} \\ 5(2 - y) = 3(y + 7) \\ 10 - 5y = 3y + 21 \\ - 5y - 3y = - 10 +21 \\ - 8y = 11 \\ y = - \frac{ - 11}{8}$

$3). \frac{(5x - 7)}{(3x)} = 2 \\ 5x - 7 = 2(3x) \\ 5x - 7 = 6x \\ 5x - 6x = 7 \\ - x = 7 \\ x = - 7$

$4). \frac{(3x + 5)}{(2x + 7)} = 4 \\ (3x + 5) = 4(2x + 7) \\ 3x + 5 = 8x + 28 \\ 3x - 8x = 28 - 5 \\ - 5x = 23 \\ x = \frac{ - 23}{ 5}$

$5). \frac{(2y + 5)}{(y + 4)} = 1 \\ 2y + 5 = y + 4 \\ 2y - y = - 5 + 4 \\ y = - 1$

Answer 2

Answer:

the 5th one has no answer as it is negative