Question

solve the following equations by completing the square method (2) 4xsquare+3x+5=0
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Answer 1

Given equation 

4x2+3x+5=0

Dividing by 4

4/4x2+3/4x+5/4=0

x2+3/4x+5/4=0

We know that 

(a+b)2=a2+2ab+b2

Here a=x

2ab=3/4x

2b=3/4

b=3/8

Adding and subtracting (3/8)2

x2+3/4x+5/4+(3/8)2−(3/8)2=0

(x+3/8)2+5/4−(3/8)2=0

(x+3/8)2=9/64−5/4

(x+3/8)2=9-80/64

(x+3/8)2= -71/64

Since square of any number cannot be negative

So, answer does not exist.

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