Question

solve the following equations by error and trial method
(1) .3A - 14 is equal to 4​

Answer 1

Answer:

A=6

Explanation:

Given that,

3A-14=4

let, A=1

then, 3(1)-14=4

=>3-14=4=>-11≠4

let,A=2

then,3(2)-14=4

=>6-14=4=>-8≠4

let,A=3

then,3(3)-14=4

=>9-14=4=>-5≠4

letA=4

then,3(4)-14=4

=>12-14=4=>-2≠4

let,A=5

then,3(5)-14=4

=>15-14=4=>1≠4

let,A=6

then,3(6)-14=4

=>18-14=4=>4=4

∴A=6

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