Solve the following equations by substitution method 1/x+2/y=9;2/x+1/y=12 [x≠0,y≠0]
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2
1/x+2/y=9 multiply with 2
2/x+4/y=18 ,2/x+1/y=12
subtract the two
2/x+4/y-2/x-1/y=18-12
4/y-1/y=6
y=1/2
x=1/5
2/x+4/y=18 ,2/x+1/y=12
subtract the two
2/x+4/y-2/x-1/y=18-12
4/y-1/y=6
y=1/2
x=1/5
Answered by
0
1/x = a 1/y = b
a + 2 b = 9 so a = 9 - 2b --- eq 1
2 a + b = 12
substitute the value of a from equation 1,
2 (9 - 2b) + b = 12
18 - 4 b +b = 12
3 b = 6 b = 2
a = 9 - 2b = 5
so x = 1/5 y = 1/2
a + 2 b = 9 so a = 9 - 2b --- eq 1
2 a + b = 12
substitute the value of a from equation 1,
2 (9 - 2b) + b = 12
18 - 4 b +b = 12
3 b = 6 b = 2
a = 9 - 2b = 5
so x = 1/5 y = 1/2
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