Math, asked by 0000000000000028, 8 hours ago

Solve the following equations by substitution method

5 x - 3 y - 8 = 0 and 2x - 3 y - 5 = 0​

Answers

Answered by krishh221
0

3y=5x-8

so 2x-(5x-8)-5=0

3x=3 and x=1

3y=5*1-8

3y=-3 and y=-1

Answered by Samraath
0

Answer:

y = -1 and x = 1

Step-by-step explanation:

5x - 3y -8 = 0...i

2x - 3y - 5 = 0...ii

  • x = (3y + 8) / 5
  • substitute the value of in eqn ii
  • 2[(3y + 8)/5] -3y -5 = 0
  • 6y + 16 -15y -25 =0

————————

5

  • -9y -9 = 0
  • y+1 = 0
  • y = -1
  • substitute the value of y in eqn I
  • 5x -3(-1) -8 = 0
  • 5x +3 -8 =0
  • 5x = 5
  • x= 1

===→ [ x= 1 and y = -1 ]

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