Math, asked by 142arumugam, 1 year ago

solve the following equations by substitution method 5x+3y=21;2x-y=4

Answers

Answered by Anonymous
1
5x + 3y = 21

2x - y = 4 multiplying 3 on both sides
6x - 3y = 12

now adding two equations

5x + 3y + 6x - 3y = 21 + 12
x = 3
y = 2x -4
y = 6- 4 = 2

Anonymous: hope it helps
Anonymous: plz mark as best
Answered by Gomisan
0
5x+3y=21
or,5x=21-3y
or,x=(21-3y)/5....................(1)
2x-y=4
putting the value of x as (21-3y)/5 from (1) we have,
(42-6y)/5-y=4
or,42-6y-5y=20
or,-11y=20-42=-22
or,y=-22/-11=2 .....................(2)
 x=(21-3y)/5 ,
putting the value of  y as 2 from (2) we have,
x=(21-6)/5=3
Ans:x=3
y=2

Gomisan: please mark it as the best one.It is done with better explanations.
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