Question

Solve the following equations by transposing the terms and check your result. (1) 2 + y = 7 (ii) 2a - 3 = 5 (iii) 10-q=6 (iv) 2t - 5=3 (v) 14 = 27 - X (vi) 5 (x+4)=35 (vii) -3x = 15 (viii) 5x –3 = 3x - 5 (ix) 3y +4= 5y - 4 (x) 3 (x - 3) = 5 (2x + 1) ​

Answer 1

Answer:

Step-by-step explanation:

1. 2+Y =7

 Y = 7-2

Y=5

2.2A - 3 = 5

2A = 5+3

2A = 8

A = 8/2

A=4

3.

10 - Q = 6

10 - 6 =Q

Q = 4

4

2T - 5 =3

2T = 3+5

2T = 8

T = 8/2

T=4

5

X - 27 = 14

X = 14+27

X=41

6

5(X + 4) = 35

5X + 20 = 35

5X = 35 - 20

5X = 15

X = 15/5

X= 3

7

-3X = 15

-15 = 3X

X = -15/3

X=-5

8

5X - 3 = 3X - 5

5X - 3X = -5 + 3

2X = -2

X = -2/2 = -1

9

3Y + 4 = 5Y - 4

5Y -3Y = 4+4

2Y = 8

Y = 8/2

Y=4

10

3(X-3) = 5(2X +1)

3X - 9 = 10X + 5

10X -3X = 5+9

7X = 14

X = 14/7

X = 2